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Since ab is negative, a & b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. The only such pair is the system solution.
(3x-3)2=16 Two solutions were found : x = -1/3 = -0.333 x = 7/3 = 2.333 Rearrange: Rearrange the equation by subtracting what is lớn the right of the equal sign from both sides of the ...
displaystylex=leftlbrace1,2 ight brace Explanation: displaystyleleft(2x-3 ight)^2=1displaystylesqrtleft(2x-3 ight)^2=sqrt1displaystyle2x-3=±1 ...
(x-3)2=11 Two solutions were found : x =(6-√44)/2=3-√ 11 = -0.317 x =(6+√44)/2=3+√ 11 = 6.317 Rearrange: Rearrange the equation by subtracting what is to lớn the right of the equal sign from ...
(x-3)2=13 Two solutions were found : x =(6-√52)/2=3-√ 13 = -0.606 x =(6+√52)/2=3+√ 13 = 6.606 Rearrange: Rearrange the equation by subtracting what is to lớn the right of the equal sign from ...
(x-3)2=14 Two solutions were found : x =(6-√56)/2=3-√ 14 = -0.742 x =(6+√56)/2=3+√ 14 = 6.742 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from ...
(x-3)2=17 Two solutions were found : x =(6-√68)/2=3-√ 17 = -1.123 x =(6+√68)/2=3+√ 17 = 7.123 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from ...
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To solve the equation, factor x^2-6x-7 using formula x^2+left(a+b ight)x+ab=left(x+a ight)left(x+b ight). Khổng lồ find a and b, mix up a system khổng lồ be solved.
Since ab is negative, a & b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. The only such pair is the system solution.
To solve the equation, factor the left hand side by grouping. First, left hand side needs to lớn be rewritten as x^2+ax+bx-7. Lớn find a & b, set up a system to be solved.
Since ab is negative, a và b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. The only such pair is the system solution.
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This equation is in standard form: ax^2+bx+c=0. Substitute 1 for a, -6 for b, & -7 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
left< eginarray l l 2 và 3 \ 5 và 4 endarray ight> left< eginarray l l l 2 và 0 và 3 \ -1 và 1 và 5 endarray ight>
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