### 1/4x^2-1/2x=1

This solution giao dịch with adding, subtracting và finding the least common multiple.

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## Step by Step Solution ### Rearrange:

Rearrange the equation by subtracting what is lớn the right of the equal sign from both sides of the equation : 1/4*x^2-1/2*x-(1)=0

## Step 1 :

1 Simplify — 2Equation at the end of step 1 : 1 1 ((—•(x2))-(—•x))-1 = 0 4 2

## Step 2 :

1 Simplify — 4Equation at the end of step 2 : 1 x ((— • x2) - —) - 1 = 0 4 2

## Step 3 :

Equation at the end of step 3 : x2 x (—— - —) - 1 = 0 4 2

## Step 4 :

Calculating the Least Common Multiple :4.1 Find the Least Common Multiple The left denominator is : 4 The right denominator is : 2

Number of times each prime factorappears in the factorization of:PrimeFactorLeftDenominatorRightDenominatorL.C.M = MaxLeft,Right
2212
Product of allPrime Factors424

Least Common Multiple: 4

Calculating Multipliers :

4.2 Calculate multipliers for the two fractions Denote the Least Common Multiple by L.C.M Denote the Left Multiplier by Left_M Denote the Right Multiplier by Right_M Denote the Left Deniminator by L_Deno Denote the Right Multiplier by R_DenoLeft_M=L.C.M/L_Deno=1Right_M=L.C.M/R_Deno=2

Making Equivalent Fractions :

4.3 Rewrite the two fractions into equivalent fractionsTwo fractions are called equivalent if they have the same numeric value. For example : một nửa and 2/4 are equivalent, y/(y+1)2 và (y2+y)/(y+1)3 are equivalent as well. To lớn calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. X2 —————————————————— = —— L.C.M 4 R. Mult. • R. Num. X • 2 —————————————————— = ————— L.C.M 4 Adding fractions that have a common denominator :4.4 Adding up the two equivalent fractions địa chỉ cửa hàng the two equivalent fractions which now have a common denominatorCombine the numerators together, put the sum or difference over the common denominator then reduce to lớn lowest terms if possible:

x2 - (x • 2) x2 - 2x ———————————— = ——————— 4 4 Equation at the end of step 4 : (x2 - 2x) ————————— - 1 = 0 4

## Step 5 :

Rewriting the whole as an Equivalent Fraction :5.1Subtracting a whole from a fraction Rewrite the whole as a fraction using 4 as the denominator :

1 1 • 4 1 = — = ————— 1 4 Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction và the other fraction involved in the calculation cốt truyện the same denominator

## Step 6 :

Pulling out like terms :6.1 Pull out lượt thích factors:x2 - 2x=x•(x - 2)

Adding fractions that have a common denominator :

6.2 Adding up the two equivalent fractions

x • (x-2) - (4) x2 - 2x - 4 ——————————————— = ——————————— 4 4 Trying khổng lồ factor by splitting the middle term6.3Factoring x2 - 2x - 4 The first term is, x2 its coefficient is 1.The middle term is, -2x its coefficient is -2.The last term, "the constant", is -4Step-1 : Multiply the coefficient of the first term by the constant 1•-4=-4Step-2 : Find two factors of -4 whose sum equals the coefficient of the middle term, which is -2.

 -4 + 1 = -3 -2 + 2 = 0 -1 + 4 = 3

Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored

Equation at the end of step 6 : x2 - 2x - 4 ——————————— = 0 4

## Step 7 :

When a fraction equals zero :7.1 When a fraction equals zero ...Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.Here"s how:

x2-2x-4 ——————— • 4 = 0 • 4 4 Now, on the left hand side, the 4 cancels out the denominator, while, on the right hand side, zero times anything is still zero.The equation now takes the shape:x2-2x-4=0

Parabola, Finding the Vertex:7.2Find the Vertex ofy = x2-2x-4Parabolas have a highest or a lowest point called the Vertex.Our parabola opens up & accordingly has a lowest point (AKA absolute minimum).We know this even before plotting "y" because the coefficient of the first term,1, is positive (greater than zero).Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x-intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to lớn be able lớn find the coordinates of the vertex.For any parabola,Ax2+Bx+C,the x-coordinate of the vertex is given by -B/(2A). In our case the x coordinate is 1.0000Plugging into the parabola formula 1.0000 for x we can calculate the y-coordinate:y = 1.0 * 1.00 * 1.00 - 2.0 * 1.00 - 4.0 or y = -5.000

Parabola, Graphing Vertex and X-Intercepts :Root plot for : y = x2-2x-4 Axis of Symmetry (dashed) x= 1.00 Vertex at x,y = 1.00,-5.00 x-Intercepts (Roots) : Root 1 at x,y = -1.24, 0.00 Root 2 at x,y = 3.24, 0.00

Solve Quadratic Equation by Completing The Square

7.3Solvingx2-2x-4 = 0 by Completing The Square.Add 4 to lớn both side of the equation : x2-2x = 4Now the clever bit: Take the coefficient of x, which is 2, divide by two, giving 1, and finally square it giving 1Add 1 khổng lồ both sides of the equation :On the right hand side we have:4+1or, (4/1)+(1/1)The common denominator of the two fractions is 1Adding (4/1)+(1/1) gives 5/1So adding khổng lồ both sides we finally get:x2-2x+1 = 5Adding 1 has completed the left hand side into a perfect square :x2-2x+1=(x-1)•(x-1)=(x-1)2 Things which are equal khổng lồ the same thing are also equal to one another. Sincex2-2x+1 = 5 andx2-2x+1 = (x-1)2 then, according khổng lồ the law of transitivity,(x-1)2 = 5We"ll refer to lớn this Equation as Eq.

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#7.3.1 The Square Root Principle says that When two things are equal, their square roots are equal.Note that the square root of(x-1)2 is(x-1)2/2=(x-1)1=x-1Now, applying the Square Root Principle to Eq.#7.3.1 we get:x-1= √ 5 địa chỉ 1 to both sides khổng lồ obtain:x = 1 + √ 5 Since a square root has two values, one positive và the other negativex2 - 2x - 4 = 0has two solutions:x = 1 + √ 5 orx = 1 - √ 5