Bạn đang xem: Solve sinx
Why it has not solution mix "$x=frac7pi 4+pi n$"? Although it satisfy the equation.
Please help quickly.

The equation is equivalent to$$ an x=-1$$ since the two functions $cos$ & $sin$ don"t vanish together so we find$$xequivfrac3pi4mod pi$$
A solution phối is a set of points that satisfies a given equation. A given equation will have only one solution set. That phối can have many descriptions. $frac 3pi4+npi$ is one description of the solution mix for this equation. $frac 7pi4+mpi$ is another description of the same set.

Note that$$frac7pi4 + npi = left(1 + frac34 ight)pi + npi = frac3pi4 + (n+1)pi,$$so you are naming the same mix of solutions but with a different indexing system.

Thanks for contributing an answer lớn magdalenarybarikova.comematics Stack Exchange!
Please be sure to answer the question. Provide details và share your research!But avoid …
Asking for help, clarification, or responding khổng lồ other answers.Making statements based on opinion; back them up with references or personal experience.Use magdalenarybarikova.comJax to format equations. magdalenarybarikova.comJax reference.
Xem thêm: Lá Sen Có Tác Dụng Lá Sen Khô Ng Ngờ Tới, Công Dụng Của Lá Sen
To learn more, see our tips on writing great answers.
Post Your Answer Discard
By clicking “Post Your Answer”, you agree lớn our terms of service, privacy policy và cookie policy
Not the answer you're looking for? Browse other questions tagged trigonometry or ask your own question.
Find the smallest positive number $p$ for which the equation $cos(psin x)=sin(p cos x)$ has a solution $xin<0,2pi>.$
How prove this equation has only one solution $cos(2x)+cosxcdotcos(sqrt(pi-3x)(pi+x))=0$
If the equation $sin^2x-asin x+b=0$ has only one solution in $(0,pi)$, then what is the range of $b$?
For which value of $t in magdalenarybarikova.combb R$ the equation has exactly one solution : $x^2 + frac1sqrtcos t2x + frac1sin t = 2sqrt2$

Site thiết kế / hình ảnh sản phẩm © 2022 Stack Exchange Inc; user contributions licensed under cc by-sa. Rev2022.4.14.41981
Your privacy
By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.