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This equation is in standard form: ax^2+bx+c=0. Substitute 4 for a, -5 for b, and -4 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
4x2-15x-4=0 Two solutions were found : x = -1/4 = -0.250 x = 4 Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 - 15x) - 4 = 0 Step 2 :Trying lớn factor by splitting ...
4x2-5x-4=0 Two solutions were found : x =(5-√89)/8=-0.554 x =(5+√89)/8= 1.804 Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 - 5x) - 4 = 0 Step 2 :Trying khổng lồ ...
-4x2-5x-4=0 Two solutions were found : x =(5-√-39)/-8=5/-8+i/8√ 39 = -0.6250-0.7806i x =(5+√-39)/-8=5/-8-i/8√ 39 = -0.6250+0.7806i Step by step solution : Step 1 :Equation at the over of step ...
9x2-35x-4=0 Two solutions were found : x = -1/9 = -0.111 x = 4 Step by step solution : Step 1 :Equation at the over of step 1 : (32x2 - 35x) - 4 = 0 Step 2 :Trying khổng lồ factor by splitting ...
x2-15x-4=0 Two solutions were found : x =(15-√241)/2=-0.262 x =(15+√241)/2=15.262 Step by step solution : Step 1 :Trying lớn factor by splitting the middle term 1.1 Factoring ...
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All equations of the form ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
This equation is in standard form: ax^2+bx+c=0. Substitute 4 for a, -5 for b, và -4 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
Quadratic equations such as this one can be solved by completing the square. In order lớn complete the square, the equation must first be in the size x^2+bx=c.
Divide -frac54, the coefficient of the x term, by 2 lớn get -frac58. Then showroom the square of -frac58 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
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Factor x^2-frac54x+frac2564. In general, when x^2+bx+c is a perfect square, it can always be factored as left(x+fracb2 ight)^2.
left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>
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